How many grams of sodium are in sodium sulfate weighing 418 grams.

univerkov | December 29, 2020 | education

Given:
m (Na2SO4) = 418 g
m (Na) -?
Decision:
M (Na2SO4) = 23 × 2 + 32 + 64 = 142 g / mol.
142 g / mol contain 46 g / mol Na,
and 418 g (Na2SO4) – m (Na).
Let’s make a proportion
142 g / mol – 46 g / mol,
418 g – m (Na).
m (Na) = (418 g × 46 g / mol): 142 g / mol = 135.4 g.
Answer: 135.4 g.

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