How many grams of sodium carbonate will be obtained if 4.48 liters of carbon dioxide have reacted with sodium oxide?

univerkov | September 17, 2021 | education

Reaction equation:
Na2O + CO2 = Na2CO3
Moles of CO2 reacted:
4.48 / 22.4 = 0.2 (mol).
Find the molar mass of sodium carbonate:
23 * 2 + 12 + 16 * 3 = 106 (g / mol).
According to the reaction equation, from 0.2 mol of carbon dioxide, we get 0.2 mol of carbonate:
0.2 * 106 = 21.2 (g).
Answer: 21.2 grams.

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