How many grams of sodium chloride will be obtained by the interaction of sodium hydroxide weighing

How many grams of sodium chloride will be obtained by the interaction of sodium hydroxide weighing 6 grams with hydrochloric acid weighing 59 grams?

NaOH + HCl = H2O + NaCl
n (NaOH) = 6/40 = 0.15 mol
n (HCl) = 59 / 36.5 = 1.62 mol
lack of alkali
therefore m (NaOH) = 0.15 * 58.5 = 8.775 g



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