How many grams of sodium hydroxide is formed by the interaction of water weighing 25 g

How many grams of sodium hydroxide is formed by the interaction of water weighing 25 g with the required amount of sodium

2Na + 2H2O = 2NaOH + H2.
For 1 mole of water or sodium, 1 mole of sodium hydroxide is formed.
Calculate the mass: (25 g: 18 g / mol) * 40 = 55.55 g.



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