How many grams of sodium hydroxide will it take to neutralize 126g of nitric acid?

Given:
m (HNO3) = 126 g

Find:
m (NaOH) -?

Solution:
1) NaOH + HNO3 => NaNO3 + H2O;
2) M (HNO3) = Mr (HNO3) = Ar (H) * N (H) + Ar (N) * N (N) + Ar (O) * N (O) = 1 * 1 + 14 * 1 + 16 * 3 = 63 g / mol;
3) n (HNO3) = m (HNO3) / M (HNO3) = 126/63 = 2 mol;
4) n (NaOH) = n (HNO3) = 2 mol;
5) M (NaOH) = Mr (NaOH) = Ar (Na) * N (Na) + Ar (O) * N (O) + Ar (H) * N (H) = 23 * 1 + 16 * 1 + 1 * 1 = 40 g / mol;
6) m (NaOH) = n (NaOH) * M (NaOH) = 2 * 40 = 80 g.

Answer: The mass of NaOH is 80 g.