How many grams of sodium oxide is formed if 4.6 g has entered into a reaction with oxygen. sodium.

Let’s execute the solution:

Let’s write the equation:
m = 4.6 g Xg -?

4Na + O2 = 2Na2O – compounds, sodium oxide was obtained.

Calculations according to the formulas of substances:
M (Na) = 22.9 g / mol;

M (Na2O) = 61.8 g / mol;

Y (Na) = m / M = 4.6 / 22.9 = 0.2 mol.

Proportion:
0.2 mol (Na) – X mol (Na2O);

-4 mol -2 mol hence, X mol (Na2O) = 0.2 * 2/4 = 0.1 mol.

Find the mass of the product:
m (Na2O) = Y * M = 0.1 * 61.8 = 6.18 g

Answer: The mass of sodium oxide is 6.18 g



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