How many grams of sodium reacts with sulfur If 15.6 g of sodium sulfide is formed.

1. We compose the reaction equation:

2 Na + S = Na2S

According to the equation: sodium – 2 mol and Na2S – 1 mol. We find their masses:

m (Na) = n * M = 2mol * 23g / mol = 46g

m (Na2S) = n * M = 1 mol * (23 * 2 + 32) = 78 g

2. Calculate the mass Na:

xg Na – 15.6 g Na2S

46 g Na – 78 g Na2S

Hence, x = 46 * 15.6 / 78 = 9.2 g.



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