How many grams of soot can be obtained when 44.2 liters of ethane are completely decomposed?

To solve the problem, we write down the equation according to its condition:
V = 44.2 liters. X g -?
1.C2H6 = 2C + 3H2 – decomposition of ethane, obtained carbon black (C), hydrogen;
2. According to the equation, we make up the proportion:
1 mole of gas at normal level – 22.4 liters;
X mol (C2H6) – 44.2 liters. hence, x mol (C2H6) = 1 * 44.2 / 22.4 = 1.97 mol;
1.97 mol (C2H6) – X mol (C);
– 1 mol -2 mol from here, X mol (C) = 1.97 * 2/1 = 3.94 mol.
3. Find the mass of carbon (C) by the formula:
m (C) = Y * M = 3.94 * 12 = 47.28 g.
Answer: in the process of decomposition, carbon (soot) with a mass of 47.28 g was obtained.