How many grams of substance and water (in milliliters) will it take to prepare an 8% solution weighing 120 kg?

Given:
ω (substances) = 8%
m solution (substance) = 120 kg = 120,000 g
ρ (water) = 1 g / ml
To find:
m (substances) -?
V (water) -?
Decision:
1) Calculate the mass of the substance in the solution:
m (substances) = ω (substances) * m solution (substances) / 100% = 8% * 120,000 / 100% = 9600 g;
2) Calculate the mass of water:
m (water) = m solution (substance) – m (substance) = 120000 – 9600 = 110400 g;
3) Calculate the volume of water:
V (water) = m (water) / ρ (water) = 110400/1 = 110400 ml.
Answer: The mass of the substance is 9600 g; volume of water – 110400 ml.