How many grams of sulfur are formed by the interaction of 11.2 liters of hydrogen sulfide with sulfur (IV) oxide?

We write down the equation of reactions.
SO2 + 2 H2S = 3 S + 2 H2O.
Using the reaction equation, we find the volume of sulfur. We write down the solution.
11.2 l H2S – x l S.
2 × 22.4 L / mol H2S – 3 × 22.4 L / mol S.
Find the unknown value of x.
X = 11.2 × 3 × 22.4 ÷ (2 × 22.4) = 11.2 × 3 ÷ 2 = 16.8 liters of sulfur.
Next, we find the mass of sulfur. We write down the solution.
n = m / M.
n = V / Vm.
m / M = V / Vm.
m = M × V / Vm.
M (S) = 32 g / mol.
m = 32 × 16.8 ÷ 22.4 = 24 g S.
This means that the mass of the formed sulfur is 24 grams.
Answer: m (S) = 24 g.