How many grams of sulfuric acid is contained in 600 ml of a solution with a molar concentration of sulfuric acid of 1.2 mol / l?

The solution of the problem:
C = n / V = m / M * V. Hence, the mass is equal to m = C * M * V = 1.2 mol / l * 98 g / mol * 0.6 l = 70.56 g.
Answer: 70.56 grams.



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