How many grams of sulfuric acid is formed when 60 grams of sulfur oxide (6) reacts with water?

univerkov | April 25, 2021 | education

Given:

m (SO3) = 60g.

m (H2SO4) -?

Decision:

1.Let’s find the amount of sulfur oxide (VI) substance by the formula:

n = m: M.

M (SO3) = 80 g / mol.

n = 60 g: 80 g / mol = 0.75 mol.

2. Let’s compose the reaction equation for the dissolution of sulfur oxide in water.

H2O + SO3 = H2SO4

According to the reaction equation, 1 mol of sulfur oxide accounts for 1 mol of acid. Substances are in quantitative ratios 1: 1. Their amount of substances will be the same.

n (SO3) = n (H2SO4) = 0.75 mol.

3. Let’s find the mass of sulfuric acid.

m = n × M.

M (H2SO4) = 1 × 2 + 32 + 16 × 4 = 98 g / mol.

m = 98 g / mol × 0.75 mol = 73.5 g.

Answer: 73.5 g.

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