How many grams of sulfuric acid is required to completely neutralize 20 g of sodium hydroxide?

univerkov | September 4, 2021 | education

We compose the reaction equation.
H2SO4 + 2NaOH = Na2SO4 + 2H2O.
Next, we find the molar mass of sulfuric acid and sodium hydroxide.
M (H2SO4) = 2 + 32 + 16 × 4 = 98 g / mol.
M (NaOH) = 23 + 16 + 1 = 40 g / mol.
Further, according to the reaction equation, we find the mass of sulfuric acid.
X g H2SO4 – 20 g NaOH.
98 g / mol Н2SO4 – 40 g / mol NaOH.
Find the unknown value of x.
X = 98 × 20 ÷ 40 = 49 g H2SO4.
This means that 49 grams of sulfuric acid is required.
Answer: m (H2SO4) = 49 g.

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