How many grams of water and aluminum chloride do you need to take to get 170g of a 25% solution.

1) m (AlCl3) = 170 * 25/100 = 42.5 (g) – aluminum chloride
2) m (H2O) = 170 – 42.5 = 127.5 (g) – water
Answer: you need to take 127.5 g of water and 42.5 g of aluminum chloride



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