How many grams of water do you need to add to 400 g of a 50% sulfuric acid solution in order to get a 10% solution?

univerkov | November 27, 2020 | education

400 * 0.5 = 200 g (pure acid)
0.1 = 200 / (400 + x)
400 + x = 2000
x = 1600 g
Answer: 1600 g

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