How many grams of water must react with potassium to make 28g of sodium hydroxide?

Reaction equation: 2K + 2H2O = 2KOH + H2
Find the amount of potassium hydroxide substance n = m / M = 28 g / 56 g / mol = 0.5 mol. According to the reaction from 2 mol of water, 2 mol of potassium hydroxide is obtained, which means n (H2O) = n (KOH) = 0.5 mol. The mass of water is m = n * M = 0.5 mol * 18 g / mol = 9 g (M is the molar mass, determined according to the periodic table).
Answer: 9 g of water is needed.



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