How many grams of water will be released when 10 g of 15% sodium hydroxide solution interacts with H2SO4.

univerkov | January 7, 2021 | education

First, we find the mass of pure acid: m = 10 * 0.15 = 1.5 g
We write the reaction equation: 2NaOH + H2SO4 = Na2SO4 + 2H2O
We make the proportion:
1.5 – x
2 * 40 – 2 * 18
x = 1.5 * 2 * 18/2 * 40 = 0.675 g of water.

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