How many grams of zinc reacted with hydrochloric acid if 10 g of hydrogen were released?

Zinc metal dissolves in hydrochloric acid with the evolution of hydrogen gas and the formation of zinc chloride. The reaction is described by the following equation:

Zn + 2HCl = ZnCl2 + H2;

1 mole of zinc reacts with 2 moles of acid. In this case, 1 mol of salt is formed and 1 mol of hydrogen gas is released.

Let’s calculate the released amount of hydrogen. To do this, we divide the weight of the synthesized hydrogen by the weight of 1 mole of gas, which is 2 grams / mole.

M H2 = 2 grams / mol; N H2 = 10/2 = 5 mol;

To synthesize such an amount of hydrogen, it is necessary to take the same amount of zinc. Let’s calculate its weight.

M Zn = 65 grams / mol; m Zn = 5 x 65 = 325 grams;