How many grams of zinc was dissolved in hydrochloric acid if 112 liters of hydrogen were released during this reaction?

Metallic zinc is actively dissolved in hydrochloric acid to form a water-soluble salt.

The chemical reaction proceeds according to the following scheme:

Zn + 2HCl → ZnCl2 + H2;

Let’s determine the chemical amount of hydrogen.

For this purpose, we divide its volume by the standard volume of 1 mole of gas, which is 22.4 liters.

N H2 = 112 / 22.4 = 5 mol;

To obtain this amount of hydrogen, it is required to dissolve the same amount of metallic zinc.

Find the weight of 5 moles of zinc. To do this, multiply the molar amount of zinc by its molar weight.

M Zn = 65 grams / mol;

m Zn = 5 x 65 = 325 grams;