How many grams of zinc will react with hydrochloric acid if you get 4.481 hydrogen?

Zinc reacts with hydrochloric acid to release hydrogen gas and form zinc chloride:

Zn + 2HCl = ZnCl2 + H2;

1 mole of metal reacts with 2 moles of acid. This synthesizes 1 mol of salt and 1 mol of hydrogen.

Let’s calculate the released amount of hydrogen. To do this, we divide the volume of synthesized hydrogen by the volume of 1 mole of gas, which is 22.4 liters.

V H2 = 4.481 liters; N H2 = 4.481 / 22.4 = 0.2 mol;

To synthesize such an amount of hydrogen, it is necessary to take the same amount of zinc. Let’s calculate its weight by multiplying the amount of substance by the weight of 1 mole of metal:

M Zn = 65 grams / mol; m Zn = 0.2 x 65 = 13.0 grams;

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