How many grams of zinc zn is formed when it is reduced with coke C from 162 g of zinc oxide containing 10% impurities?

Let’s implement the solution:

Let’s write the data:
m = 162 g 10% impurities;

2ZnO + C = 2Zn + CO2 – OBP, zinc formed;

Let’s make the calculations:
M (ZnO) = 81.3 g / mol;

M (Zn) = 65.3 g / mol;

m (ZnO) = 162 * (1 – 0.10) = 145.8 g (weight without impurity);

Y (ZnO) = m / M = 145.8 / 81.3 = 1.8 mol;

Y (Zn) = 1.8 mol since the amount of substances is 2 mol.

Determine the mass of the metal:
m (Zn) = Y * M = 1.8 * 65.3 = 117.5 g

Answer: Zinc was obtained with a mass of 117.5 g.