How many heat released during the hardened 500 grams of tin and its further cooling to 32 ° C?

univerkov | June 28, 2021 | education

Source data: M (tin mass) = 500 g = 0.5 kg; T0 (Tin temperature after crystallization and cooling) = 32 ºС.

Permanent: C (specific soot of tin) = 230 J / (kg * k); λ (specific heat of melting tin) = 0.59 * 10 ^ 5 j / kg; t (melting point, tin crystallization) = 232 ºС.

The highlighted heat is calculated by the formula: Q = Q1 (tin crystallization) + q2 (tin cooling) = λ * M + C * M * (T – T0).

Calculation: Q = 0.59 * 10 ^ 5 * 0.5 + 230 * 0.5 * (232 – 32) = 52 500 J = 52.5 kJ.

One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.