How many identical 200 ohm resistors would it take to get a 1.6k loop resistance?

To find the required number of identical resistors connected in series, we apply the formula (the connection cannot be parallel, since in this case the total resistance will be less than 200 Ohms): R = n * R1, from where we express: n = R / R1.

The values of the variables: R is the total resistance of the circuit (R = 1.6 kOhm = 1600 Ohm); R1 is the resistance of one resistor (R1 = 200 Ohm).

Calculation: n = R / R1 = 1600/200 = 8 resistors.

Answer: You need 8 identical resistors.



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