How many iron and oxygen atoms are contained in iron oxide (lll) with an amount of a substance of 3 mol?

Given:
N (Fe2O3) = 3 mol
Decision:
3 * 2 = 6 moles of iron
3 * 3 = 9 moles of oxygen
6.02 * 6 * 10 ^ 23 = 36.12 * 10 ^ 23 iron atoms
6.02 * 9 * 10 ^ 23 = 54.18 * 10 ^ 23-oxygen atoms
Answer: 36.12 * 10 ^ 23 iron atoms; 54.18 * 10 ^ 23 oxygen atoms.



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