How many KB will be in a message of 4096 characters in a 512-character alphabet?

Given:

N (power of the alphabet) = 512 characters;

K (number of characters) – 4096 characters;

Unknown:

I (amount of information) =?

i (character weight) -?

We can solve this problem using the formulas:

N = 2 ^ i, I = K * i;

2 ^ 9 = 512;

i = 9 bits;

Substitute the values:

I = K * i;

4096 * 9 = 36 864 bits;

36 864/8 = 4 608 bytes;

4 608/1024 = 4.5 Kilobytes.