To find the amount of information that will be transmitted over a channel with a given bandwidth in 1 second, it is necessary to convert 10 MBit to KB.
First, let’s convert from bits to bytes. There are 8 bits in one byte, which means 10 MBit = 10/8 MByte.
Now let’s convert from MByte to KByte. One MByte is 1024 KByte. This means that for translation it is necessary to multiply 10/8 by 1024. After that, the result obtained is the required amount of information. We get 1280 KB in 1 second.
Answer: 1280 kB.
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