How many kg of magnesium oxide can be obtained by decomposing magnesium carbonate with a mass

How many kg of magnesium oxide can be obtained by decomposing magnesium carbonate with a mass of 10 kg if the reaction yield is 90% of the theoretical?

1) Let’s compose the reaction equation: MgCO3 ==> MgO + CO2 ^
2) Determine the theoretical yield of oxide: 10 kg (MgCO3) ==> 84 kg / mol (MgCO3) x kg (MgO) ==> 40 kg / mol hence m theor (MgO) = 40 kg / mol * 10 kg / 84 kg / mol = 4.76 kg
3) Determine the practical yield of oxide: 4.76 kg (MgO) ==> 100% x kg (MgO) ==> 90% hence m pr (MgO) = 90% * 4.76 kg / 100% = 4.284 kg
Answer: m pr (MgO) = 4.284 kg