How many kg of phenol can be obtained from potassium phenolate with a mass of 10 kg? How many liters of sulfuric
| December 8, 2020 | education
How many kg of phenol can be obtained from potassium phenolate with a mass of 10 kg? How many liters of sulfuric acid solution (pl1.8) with a mass fraction of H2SO4 90% will be consumed?
C6H5OK + H2SO4 = C6H5OH + KHSO4
n (C6H5OK) = 10000 grams / 132 = 75.76 mol
m (C6H5OH) = 75.76 * 94 = 7121.5 grams = 7.1 kg
m (H2SO4) = 75.76 * 98 = 7424.5 grams
V = m / p = 7424.5 / 1.8 = 4124.7 liters
4124.7 * 0.9 = 3712 liters
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