How many kg of phosphoric acid can be obtained from 200 kg of phosphorus oxide if the acid yield

How many kg of phosphoric acid can be obtained from 200 kg of phosphorus oxide if the acid yield is 75% compared to theoretical

Let’s execute the solution:

According to the condition of the problem, we write down the equation of the process:
P2O5 + 3H2O = 2H3PO4 – compounds, phosphoric acid was released;

Let’s make the calculations:
M (P2O5) = 141.8 g / mol;

M (H3PO4) = 97.9 g / mol;

m (P2O5) = 200,000 g;

Y (P2O5) = m / M = 200000 / 141.8 = 1410 mol.

Proportion:
1410 mol (P2O5) – X mol (H3PO4);

-1 mol -2 mol hence, X mol (H3PO4) = 1410 * 2/1 = 2820 mol.

We find the mass of acid, taking into account the yield of the product:
m (H3PO4) = Y * M = 2820 * 97.9 = 276078 g = 276 kg 078 g (theoretical weight);

W = m (practical) / m (theoretical) * 100;

m (H3PO4) = 0.75 * 276078 = 207058.5 g = 207 kg 058 g

Answer: received orthophosphoric acid weighing 207 kg 058 g