How many kilograms of 68% nitric acid can be obtained from 276 kg of nitric oxide 4

| February 5, 2021 | education

From nitric oxide (4), nitric acid can be obtained using three possible reactions:

4NO2 (l) + H2O (cold) = 2HNO3 + N2O3
3NO2 + H2O (hot) = 2HNO3 + NO ↑
4NO2 + O2 + 2H2O = 4HNO3

In the first two variants, in addition to nitric acid, other nitrogen oxides are formed, and in the third reaction, all nitrogen from the oxide passes into the acid. It is the most economical, so we will use it to calculate:

Let us determine the number of moles in 276 kg of nitrogen oxide (4). Its molar mass is 14 + 16 x 2 = 46 grams / mol.

The number of moles of nitric oxide (4) is 276 x 1000/46 = 6000 mol.

The same number of moles of nitric acid can be obtained.

Its molar mass is 1 + 14 + 16 x 3 = 63 grams / mol.

Theoretically, the possible mass of 100% nitric acid will be 6000 x 63 = 378 kilograms.

If it is diluted with water to 68%, then such nitric acid will weigh 378 / 0.68 = 555.88 kilograms.



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