How many kilograms of calcium oxide are obtained when decomposing 250kg. calcium

How many kilograms of calcium oxide are obtained when decomposing 250kg. calcium carbonate containing 20% impurities? what volume of carbon dioxide – carbon monoxide (IV) will be released?

The decomposition reaction of calcium carbonate is described by the following chemical reaction equation:

CaCO3 = CaO + CO2;

From one mole of calcium carbonate, one mole of calcium oxide and carbon monoxide is formed.

Determine the mass of pure calcium carbonate.

m CaCO3 = 250,000 x 80% = 200,000 grams;

Let’s determine the amount of a substance in 200,000 grams of calcium carbonate.

Its molar mass is:

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;

The amount of the substance will be:

N CaCO3 = 200,000 / 100 = 2,000 mol;

The same amount of carbon monoxide and calcium oxide will be obtained.

Under normal conditions, one mole of ideal gas takes up a volume of 22.4 liters.

Let’s determine the volume of carbon dioxide:

V CO2 = 2,000 x 22.4 = 44,800 liters;

The molar mass of calcium oxide is:

M CaO = 40 + 16 = 56 grams / mol;

The mass of calcium oxide will be:

m CaO = 56 x 2,000 = 112,000 grams = 112 kg;



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