How many kilograms of calcium oxide will be obtained from the decomposition of 300 kg

How many kilograms of calcium oxide will be obtained from the decomposition of 300 kg of calcium carbonate containing 20% impurities? How much (under normal conditions) carbon dioxide will be released?

The thermal decomposition reaction of calcium carbonate is described by the following chemical reaction equation:

CaCO3 = CaO + CO2 ↑;

Let’s determine the chemical amount of calcium carbonate. To do this, we divide its weight by the mass of 1 mole of the substance.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;

N CaCO3 = 300,000 x 0.8 / 100 = 2,400 mol;

The same molar amounts of calcium oxide and carbon dioxide can theoretically be obtained.

To find its volume, it is necessary to multiply the amount of substance by the volume of 1 mole of gas (which is 22.4 liters).

V СО2 = 2,400 x 22.4 = 53,760 liters = 53.76 m3;

Let’s calculate the weight of calcium oxide. To do this, we multiply the amount of the substance by the weight of 1 mole of the substance.

M CaO = 40 + 16 = 56 grams / mol;

m CaO = 56 x 2400 = 134 400 grams = 134.4 kg;