How many kilograms of carbon dioxide should be released when firing 500 kg of limestone containing 92% calcium carbonate.

The limestone decomposition reaction is described by the following chemical reaction equation:
CaCO3 = CaO + CO2;
The decomposition of 1 mol of limestone synthesizes 1 mol of gaseous carbon dioxide.
Let’s calculate the available chemical amount of calcium carbonate substance.
M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;
N CaCO3 = 500,000 x 0.92 / 100 = 4,600 mol;
During the reaction, the same amount of carbon dioxide will be synthesized.
Let’s calculate its weight.
M CO2 = 12 + 16 x 2 = 44 grams / mol;
m CO2 = 44 x 4600 = 202.4 kg;