How many kilograms of nitric acid to obtain from 134.4 m3 of nitric oxide (4)?

Let’s find the amount of the substance hydrogen.

V = Vn n, where Vn is the molar volume of gas, equal to 22.4 l / mol, and n is the amount of substance.

n = V: Vn.

n = 134.4 m3: 22.4 kg / kmol = 6 kmol.

Let’s compose the reaction equation, find the quantitative ratios of substances.

4NO2 + O2 + 2H2O = 4HNO3

According to the reaction equation, 4 kmol of nitric oxide accounts for 4 kmol of nitric acid. Substances are in quantitative ratios 1: 1.

The amount of substance will be equal.

n (NO2) = n (HNO3) = 6 kmol.

Let’s find the mass of nitric acid.

m = n × M.

M (HNO3) = 63 kg / kmol.

m = 63kg / kmol × 6 kmol = 378 kg.

Answer: 378 kg.