How many kilograms of sodium nitrate is required to prepare 2 kg of 63% nitric acid solution?

| September 14, 2021 | education

Find the mass of nitric acid in the solution.

W = m (substance): m (solution) × 100%,

hence m (substance) = (m (solution) × w): 100%.

m (substance) = (2 kg × 63%): 100% = 1.26 kg = 1260 g.

Let’s find the amount of nitric acid substance by the formula:

n = m: M.

M (HNO3) = 1 + 14 + 16 × 3 = 63 g / mol.

n = 1260 g: 63 g / mol = 2 mol.

Let’s compose the equation of the reaction between sulfuric acid and sodium bicarbonate.

H2SO4 + NaNO3 = NaHSO4 + HNO3.

Let’s find the quantitative ratios of substances.

For 1 mol of nitric acid, 1 mol of sodium nitrate NaNO3.

The substances are in a 1: 1 ratio, that is, the amounts of nitric acid and sodium nitrate will be equal.

n (HNO3) = n (NaNO3) = 2 kmol = 20 mol.

Let’s find the mass of NaNO3 by the formula:

m = n × M,

M (NaNO3) = 23 + 14 + 16 × 3 = 85 g / mol.

m = 20 mol × 85 g / mol = 1700 g = 1.7 kg.

Answer: 1.7 kg.



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