How many kilograms of water do you need to evaporate from 0.5 tons of a mixture containing 85% water to obtain

How many kilograms of water do you need to evaporate from 0.5 tons of a mixture containing 85% water to obtain a mixture containing 75% water?

0.5 t = 500 kg
if water is 85%, then the rest of the substance is 15% or 500 × 0.15 = 75 (kg).
To obtain a mixture with a water content of 75% → Ost. substances 25%, you need to make the following proportion:
25% -75 kg
75% – x kg
x = 75 × 75 ÷ 25 = 225 kg – water in the new mixture.
500 × 0.85 = 425 (kg) – there was initially water.
425-225 = 200 (kg) – water needs to be evaporated.
Answer: 200 kg of water.