How many liters of 0.1 normal silver nitrate solution is required to interact with 0.5 liters of 0.3 normal aluminum chloride solution?
| November 29, 2020 | education
In order to find out, we will compose an equation and solve it, and as a result we will find out the answer to the question:
V (AgNO3) = (Vх.а. * Nх.а.) / N (AgNO3) = 0.5 * 0.3 / 0.1 = 1.5Н
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