How many liters of 96% ethyl alcohol will be required to prepare 100 liters of 20% ethyl alcohol?

W1 = 96%.

W2 = 20%.

V2 = 100 HP

Let’s determine the volume of 96 percent alcohol. We write down the solution.

First, we find the volume of 20 percent alcohol.

90 * 20 = 1800 l.

Next, we determine the volume of 96 about alcohol. We write down the solution.

1800 l: 96 = 18.75 l.

This means that 18.75 liters of 96 percent alcohol will be required in order to prepare 100 liters of 20 percent alcohol.

Answer: 18.75 liters of 96 percent alcohol will be required.