How many liters of air and oxygen is required for the complete combustion of acetylene with a mass of 13 kg.

The oxidation reaction of acetylene is described by the following chemical reaction equation.

C2H2 + 5/2 O2 = 2CO2 + H2O;

According to the coefficients of this equation, 2.5 oxygen molecules are required to oxidize 1 acetylene molecule. In this case, 2 molecules of carbon dioxide are synthesized.

Let’s calculate the amount of acetylene available.

To do this, we divide the mass of the substance by its molar weight.

M C2H2 = 12 x 2 + 2 = 26 grams / mol;

N C2H2 = 13000/26 = 500 mol;

The required amount of oxygen will be 500 x 2.5 = 750 mol.

Let’s calculate the gas volume. To do this, we multiply the amount of substance by the volume of 1 mole of gas.

Its volume will be: V O2 = 750 x 22.4 = 16 800 liters; Provided that the volume fraction of oxygen in the air is 21%, the required volume of air will be 16800 / 0.21 = 80,000 liters;