How many liters of ammonia are formed under normal conditions when 5 moles of hydrogen react with nitrogen?

1) Let’s compose the reaction equation: 3H2 + N2 ==> 2NH3
2) According to the reaction equation, we have 3 mol (H2), and according to the condition of the problem, 5 mol, then we determine the amount of ammonia in 3 mol (H2) => 2 mol (NH3) 5 mol (H2) ==> x mol ( NH3) therefore n (NH3) = 5 mol * 2 mol / 3 mol = 3.3 mol
3) Determine the volume of ammonia: V (NH3) = Vm (NH3) * n (NH3) = 44.8 l / mol * 3.3 mol = 147.84 l
Answer: V (NH3) = 147.84 l