How many liters of ammonia will be released when ammonium sulfate reacts with 600 grams of 15% sodium hydroxide solution?

This reaction proceeds according to the following chemical reaction equation:

(NH4) 2SO4 + 2NaOH = 2NH3 + Na2SO4 + 2H2O;

Find the chemical amount of sodium hydroxide. To do this, we divide its weight by its molar mass.

M NaOH = 23 + 16 + 1 = 40 grams / mol;

N NaOH = 600 x 0.15 / 40 = 2.25 mol;

The reaction can produce the same amount of ammonia.

Let’s define its volume. For this purpose, we multiply the amount of substance by the volume of one mole of gas, which is 22.4 liters.

V NH3 = 2.25 x 22.4 = 50.4 liters;