How many liters of butane were burned if 175 liters of carbon dioxide were formed as a result?

1. We write down the equation:
2С4Н10 + 13О2 = 8СО2 + 10Н2О + Q – the butane combustion reaction is accompanied by the release of heat, carbon dioxide and water;
2. Calculations:
M (C4H10) = 58 g / mol;
M (CO2) = 44 g / mol.
3. Proportions:
1 mole of gas at normal level – 22.4 liters;
X mol (CO2) – 175 liters. hence, X mol (CO2) = 1 * 175 / 22.4 = 7.8 mol;
X mol (C4H10) – 7.8 mol (CO2);
-2 mol – 8 mol from here, X mol (C4H10) = 2 * 7.8 / 8 = 1.95 mol.
4. Find the volume of the original substance:
V (C4H10) = 1.95 * 22.4 = 43.68 l.
Answer: 43.68 liters are needed for the combustion process. butane