How many liters of carbon dioxide are formed by the interaction of sodium carbonate and 200 g of 18% hydrochloric acid.

| January 15, 2021 | education

Find the mass of hydrochloric acid in the solution.
Mass fraction of a substance is calculated by the formula:
W = m (substance): m (solution) × 100%,
m (substance) = (m (solution) × W): 100%,
m (substance) = (200 g × 18%): 100% = 36 g.
Find the amount of hydrochloric acid substance by the formula:
n = m: M.
М (HCl) = 36.5 g / mol.
n = 36 g: 36.5 g / mol = 0.98 mol.
Let’s compose the reaction equation, find the quantitative ratios of substances.
Na2CO3 + 2HCl = 2NаСl + CO2 ↑ + Н2О.
According to the reaction equation, 2 mol of hydrochloric acid accounts for 1 mol of carbon dioxide. The substances are in quantitative ratios of 2: 1.
The amount of carbon dioxide substance will be 2 times less than that of hydrochloric acid
n (CO2) = ½ n (HCl) = 0.98: 2 = 0.49 mol.
Let’s find the volume of carbon dioxide.
V = Vn n, where Vn is the molar volume of gas, equal to 22.4 l / mol, and n is the amount of substance.
V = 0.49 mol × 22.4 L / mol = 10.98 L.
Answer: 10.98 liters.



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