How many liters of carbon dioxide are produced by decomposing 40g of limestone?

The decomposition reaction of calcium carbonate is described by the following chemical reaction equation:

CaCO3 = CaO + CO2;

From one mole of calcium carbonate, one mole of calcium oxide and carbon monoxide is formed.

Determine the amount of substance in 40 grams of calcium carbonate.

Its molar mass is:

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;

The amount of the substance will be:

N CaCO3 = 40/100 = 0.4 mol;

The same amount of carbon monoxide and calcium oxide will be obtained.

Under normal conditions, one mole of ideal gas takes up a volume of 22.4 liters.

Let’s determine the volume of carbon dioxide:

V CO2 = 0.4 x 22.4 = 8.96 liters;