How many liters of carbon dioxide are released when burning 96 g of ethane?
February 23, 2021 | education
| The ethane oxidation reaction is described by the following chemical reaction equation.
2C2H6 + 7O2 = 4CO2 + 6H2O;
According to the coefficients of this equation, 7 oxygen molecules are required to oxidize 2 ethane molecules. This synthesizes 4 molecules of carbon dioxide.
Let’s calculate the amount of ethane available.
To do this, divide the available weight by the weight of 1 mole of this gas.
M C2H6 = 12 x 2 + 6 = 30 grams / mol;
N C2H6 = 96/30 = 3.2 mol;
The amount of carbon dioxide will be.
N CO2 = N C2H6 x 2 = 3.2 x 2 = 6.4 mol;
Let’s calculate the gas volume. To do this, multiply the amount of substance by the volume of 1 mole of gas.
Its volume will be: V CO2 = 6.4 x 22.4 = 143.36 liters;
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