How many liters of carbon dioxide during combustion of 48 g of methane.

univerkov | December 11, 2020 | education

We compose the equations:
CH4 + 2O2 = CO2 + 2H2O
n (CH₄) = 48/16 = 3 (mol)
x (CO₂) = 3 * 1/1 = 3 (mol)
V (CO₂) = 3 * 22.4 = 67.2 (dm3) (dm in the third degree)

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