How many liters of carbon monoxide (lV) will be obtained when 2.24 g of butadiene-1.3 are burned?

To solve, we write the equation:
1. 2H2C = CH – CH = CH2 + 11O2 = 8CO2 + 6H2O – the combustion reaction of butadiene – 1.3 is accompanied by the release of carbon dioxide, water;
2. Calculations:
M (C4H6) = 54 g / mol;
M (CO2) = 44 g / mol.
3. We make the proportion:
0.04 mol (C4H6) – X mol (CO2);
– 2 mol                   – 8 mol from here, X mol (CO2) = 0.04 * 8/2 = 0.16 mol.
4. Find the volume of the product:
V (CO2) = 0.16 * 22.4 = 3.58 liters.
Answer: during combustion, carbon monoxide (2) with a volume of 3.58 liters is released.