How many liters of chlorine can be obtained if we take manganese (IV) oxide and 300 g of hydrochloric acid
| December 23, 2020 | education
How many liters of chlorine can be obtained if we take manganese (IV) oxide and 300 g of hydrochloric acid with a mass fraction of hydrogen chloride of 15%.
Solution to this problem:
MnO2 + 4HCl = MnCl2 + Cl2 + 2H2O
Let’s compose:
n (HCl) = (300 * 0.15) / 36.5 = 1.2 mol
n (Cl2) = 1.2 / 4 = 0.3 mol
V (Cl2) = 0.3 * 22.4 = 6.72 L
Answer: 6.72 L
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