How many liters of chlorine will be absorbed by 400 ml of sodium hydroxide with a mass fraction

| September 4, 2021 | education

How many liters of chlorine will be absorbed by 400 ml of sodium hydroxide with a mass fraction of 28% if density = 1.310 g / cm ^ 3?

V (NaOH) = 400 ml.
p (NaOH) = 1.310 g / cm’3.
W = 28%.
Let’s determine the amount of chlorine. We write down the solution.
We compose the reaction equation.
2NaOH + Сl2 = NaClO + NaCl + H2O.
Find the mass of the sodium hydroxide solution.
m = p * V.
m (NaOH) = 400 * 1.310 = 524 g.
Next, we find the soluble sodium hydroxide substance. We write down the resulting solution.
W = m r.v / m r-ra * 100%.
m r.v = m solution * W / 100%.
m p.v. = 524 * 28/100 = 146.71 g.
Further, according to the reaction equation, we find the mass of chlorine.
M (NaOH) = 23 + 1 + 16 = 40 g / mol.
M (Cl2) = 2 * 35.5 = 71 g / mol.
146.71 g NaOH – x g Cl2
2 * 40 g / mol NaOH – 71 g / mol Cl2
X = 146.71 * 71: (2 * 40) = 130.214 g.
n = m / M.
n = V / Vm.
V = m * Vm / M.
V = 130.214 * 22.4 / 71 = 41.1 ml.
Answer: the volume is 41.1 ml.



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