How many liters of chlorine will be released when 1 mol of sodium dichromate interacts

How many liters of chlorine will be released when 1 mol of sodium dichromate interacts with an excess of hydrochloric acid?

Let’s implement the solution:

Let’s write down the data on the condition of the problem:
Y = 1 mol Chl -?

Na2Cr2O7 + 14HCl = 2NaCl + 2CrCl3 + 3Cl2 + 7H2O – OBP, chlorine is evolved;

Proportion:
1 mol (Na2Cr2O7) – X mol (Cl2);

-1 mol -3 mol from here, X mol (Cl2) 1 * 3/1 = 3 mol.

Find the volume of the product:
V (Cl2) = 3 * 22.4 = 67.2 L

Answer: we obtained chlorine in a volume of 67.2 liters.